3h^2+4h+1=225

Solution for 3h^2+4h+1=225 equation:

3h^2+4h+1=225

We move all terms to the left:

3h^2+4h+1-(225)=0

We add all the numbers together, and all the variables

3h^2+4h-224=0

a = 3; b = 4; c = -224;
Δ = b2-4ac
Δ = 42-4·3·(-224)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-52}{2*3}=\frac{-56}{6}
=-9+1/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+52}{2*3}=\frac{48}{6}
=8
$